25x^2-16x=40x

Solution for 25x^2-16x=40x equation:

25x^2-16x=40x

We move all terms to the left:

25x^2-16x-(40x)=0

We add all the numbers together, and all the variables

25x^2-56x=0

a = 25; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·25·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*25}=\frac{0}{50}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*25}=\frac{112}{50}
=2+6/25
$